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Simplifying 3[x + 1] + 1 + 2x = 2[2x + 2] + x Reorder the terms: 3[1 + x] + 1 + 2x = 2[2x + 2] + x [1 * 3 + x * 3] + 1 + 2x = 2[2x + 2] + x [3 + 3x] + 1 + 2x = 2[2x + 2] + x Reorder the terms: 3 + 1 + 3x + 2x = 2[2x + 2] + x Combine like terms: 3 + 1 = 4 4 + 3x + 2x = 2[2x + 2] + x Combine like terms: 3x + 2x = 5x 4 + 5x = 2[2x + 2] + x Reorder the terms: 4 + 5x = 2[2 + 2x] + x 4 + 5x = [2 * 2 + 2x * 2] + x 4 + 5x = [4 + 4x] + x Combine like terms: 4x + x = 5x 4 + 5x = 4 + 5x Add '-4' to each side of the equation. 4 + -4 + 5x = 4 + -4 + 5x Combine like terms: 4 + -4 = 0 0 + 5x = 4 + -4 + 5x 5x = 4 + -4 + 5x Combine like terms: 4 + -4 = 0 5x = 0 + 5x 5x = 5x Add '-5x' to each side of the equation. 5x + -5x = 5x + -5x Combine like terms: 5x + -5x = 0 0 = 5x + -5x Combine like terms: 5x + -5x = 0 0 = 0 Solving 0 = 0 Couldn't find a variable to solve for. This equation is an identity, all real numbers are solutions.
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